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JEE Main Physics Class 11 Oscillations Part 1 Questions
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© examsnet.com
Question : 5
Total: 100
A particle executes simple harmonic motion represented by displacement function as
x
(
t
)
=
A
sin
(
ω
t
+
ϕ
)
If the position and velocity of the particle at
t
=
0
s
are
2
c
m
and
2
ω
c
m
s
−
1
respectively, then its amplitude is
x
√
2
c
m
where the value of
x
is ____.
[27 Jul 2021 Shift 2]
Your Answer:
Validate
Solution:
x
(
t
)
=
A
sin
(
ω
t
+
ϕ
)
v
(
t
)
=
A
ω
cos
(
ω
t
+
ϕ
)
2
=
A
sin
ϕ
........(1)
2
ω
=
A
ω
cos
ϕ
.......(2)
From (1) and (2)
tan
ϕ
=
1
ϕ
=
45
°
Putting value of
ϕ
in equation (1)
2
=
A
{
1
√
2
}
A
=
2
√
2
x
=
2
© examsnet.com
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