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JEE Main Physics Class 11 Oscillations Part 1 Questions
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© examsnet.com
Question : 8
Total: 100
A particle is making simple harmonic motion along the X-axis. If at a distances
x
1
and
x
2
from the mean position the velocities of the particle are
v
1
and
v
2
respectively. The time period of its oscillation is given as:
[20 Jul 2021 Shift 2]
T
=
2
π
√
x
2
2
+
x
1
2
v
1
2
−
v
2
2
T
=
2
π
√
x
2
2
+
x
1
2
v
1
2
+
v
2
2
T
=
2
π
√
x
2
2
−
x
1
2
v
1
2
+
v
2
2
T
=
2
π
√
x
2
2
−
x
1
2
v
1
2
−
v
2
2
Validate
Solution:
v
2
=
ω
2
(
A
2
−
x
2
)
A
2
=
x
1
2
+
v
1
2
ω
2
=
x
2
2
+
v
2
2
ω
2
ω
2
=
v
2
2
−
v
1
2
x
1
2
−
x
2
2
T
=
2
π
√
x
2
2
−
x
1
2
v
1
2
−
v
2
2
© examsnet.com
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