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JEE Main Physics Class 11 Oscillations Part 2 Questions
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© examsnet.com
Question : 20
Total: 76
A particle is executing simple harmonic motion (SHM). The ratio of potential energy and kinetic energy of the particle when its displacement is half of its amplitude will be
[12-Apr-2023 shift 1]
1
:
1
1
:
3
1
:
4
2
:
1
Validate
Solution:
Ratio of
PE
and
KE
=
?
When
x
x
\
disp.
=
A
2
KE
=
1
2
m
ω
2
[
A
2
−
x
2
]
=
1
2
m
ω
2
[
A
2
−
A
2
4
]
KE
=
=
1
2
m
ω
2
[
3
A
2
4
]
... (1)
And
PE
=
1
2
m
ω
2
x
2
=
1
2
m
ω
2
A
2
4
PE
KE
=
m
ω
2
A
2
×
8
8
m
ω
2
A
2
×
3
=
1
3
⇒
1
:
3
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