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JEE Main Physics Class 11 Oscillations Part 2 Questions
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© examsnet.com
Question : 37
Total: 76
The general displacement of a simple harmonic oscillator is
x
=
A
s
i
n
ω
t
. Let
T
be its time period. The slope of its potential energy (U) - time (t) curve will be maximum when
t
=
T
β
. The value of
β
is _______.
[30-Jan-2023 Shift 1]
Your Answer:
Validate
Solution:
x
=
A
s
i
n
(
ω
t
)
U
(
x
)
=
1
2
kx
2
dU
dt
=
1
2
k
2
x
dx
dt
=
kA
2
ω
s
i
n
ω
t
cos
ω
t
×
2
2
(
dU
dt
)
max
=
kA
2
ω
2
(
s
i
n
2
ω
t
)
max
2
ω
t
=
π
2
⇒
t
=
π
4
ω
=
T
8
⇒
β
=
8
© examsnet.com
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