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JEE Main Physics Class 11 Oscillations Part 2 Questions
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© examsnet.com
Question : 46
Total: 76
A compass needle of oscillation magnetometer oscillates 20 times per minute at a place
P
of
dip
30
∘
. The number of oscillations per minute become 10 at another place
Q
of
60
∘
dip. The ratio of the total magnetic field at the two places
(
B
Q
:
B
P
)
is :
[27-Jul-2022-Shift-2]
√
3
:
4
4
:
√
3
√
3
:
2
2
:
√
3
Validate
Solution:
T
=
2
π
√
I
B
H
M
T
1
=
3
s
e
c
=
2
π
√
I
(
B
P
cos
30
∘
)
M
T
2
=
6
s
e
c
=
2
π
√
I
(
B
Q
cos
60
∘
)
M
3
6
=
√
1
(
B
P
√
3
2
)
×
(
B
Q
∕
2
)
3
6
=
√
(
B
Q
√
3
B
P
)
√
3
4
=
B
Q
B
P
B
Q
:
B
P
=
√
3
:
4
© examsnet.com
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