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JEE Main Physics Class 11 Physical world and Measurements Part 1 Questions
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Question : 32
Total: 100
A student measuring the diameter of a pencil of circular cross-section with the help of a vernier scale records the following four readings 5.50 mm, 5.55 mm, 5.45 mm, 5.65 mm, The average of these four reading is 5.5375 mm and the standard deviation of the data is 0.07395 mm. The average diameter of the pencil should therefore be recorded as :
[Sep. 06, 2020 (II)]
(5.5375 ± 0.0739) mm
(5.5375 ± 0.0740) mm
(5.538 ± 0.074) mm
(5.54 ± 0.07) mm
Validate
Solution:
Average diameter,
d
av
= 5.5375 mm
Deviation of data, Δd = 0.07395 mm
As the measured data are upto two digits after decimal, therefore answer should be in two digits after decimal.
∴ d = (5.54 ± 0.07) mm
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