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Test Index
JEE Main Physics Class 11 Physical world and Measurements Part 1 Questions
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© examsnet.com
Question : 38
Total: 100
A simple pendulum is being used to determine the value of gravitational acceleration g at a certain place. The length of the pendulum is 25.0 cm and a stop watch with 1 s resolution measures the time taken for 40 oscillations to be 50 s. The accuracy in g is:
[8 Jan. 2020 II]
5.40%
3.40%
4.40%
2.40%
Validate
Solution:
Given, Length of simple pendulum, l = 25.0 cm
Time of 40 oscillation, T = 50s
Time period of pendulum
T
=
2
π
√
l
g
⇒
T
2
=
4
π
2
l
g
⇒
g
=
4
π
2
l
T
2
⇒ Fractional error in
g
=
Δ
g
g
=
Δ
l
l
+
2
Δ
T
T
⇒
Δ
g
g
=
(
0.1
25.0
)
+
2
(
1
50
)
=
0.044
∴ Percentage error in
g
=
Δ
g
g
×
100
=
4.4
%
© examsnet.com
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