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JEE Main Physics Class 11 Physical world and Measurements Part 1 Questions
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Question : 67
Total: 100
A screw gauge with a pitch of 0.5 mm and a circular scale with 50 divisions is used to measure the thickness of a thin sheet of Aluminium. Before starting the measurement, it is found that wen the two jaws of the screw gauge are brought in contact, the 45th division coincides with the main scale line and the zero of the main scale is barely visible. What is the thickness of the sheet if the main scale reading is 0.5 mm and the 25th division coincides with the main scale line?
[2016]
0.70 mm
0.50 mm
0.75 mm
0.80 mm
Validate
Solution:
L
.
C
.
=
0.5
50
=
0.01
mm
Zero error = 5 × 0.01 = 0.05 mm (Negative)
Reading = (0.5 + 25 × 0.01) + 0.05 = 0.80 mm
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