Let µ0 related with e,m,c and h as follows. µ0=keambcchd [MLT−2A−2]=[AT]a[M]b[LT−1]c[ML2T−1]d =[Mb+dLc+2dTa−c−dAa] On comparing both sides we get a = – 2 ...(i) b + d = 1 ...(ii) c + 2d = 1 ...(iii) a – c – d = –2 ...(iv) By equation (i), (ii), (iii) & (iv) we get, a = – 2, b = 0, c = – 1, d = 1 ∴[µ0]=[