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JEE Main Physics Class 11 Physical world and Measurements Part 1 Questions
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© examsnet.com
Question : 74
Total: 100
In terms of resistance R and time T, the dimensions of ratio
µ
ε
of the permeability m and permittivity
ε
is:
[Online April 11, 2014]
[
R
T
−
2
]
[
R
2
T
−
1
]
[
R
2
]
[
R
2
T
2
]
Validate
Solution:
Dimensions of
µ
=
[
M
L
T
−
2
A
−
2
]
Dimensions of
ε
=
[
M
−
1
L
−
3
T
4
A
2
]
Dimensions of
R
=
[
M
L
2
T
−
3
A
−
2
]
∴
Dimensions of
µ
Dimensions of
ε
=
[
M
L
T
−
2
A
−
2
]
[
M
−
1
L
−
3
T
4
A
2
]
=
[
M
2
L
4
T
−
6
A
−
4
]
=
[
R
2
]
© examsnet.com
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