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JEE Main Physics Class 11 Physical world and Measurements Part 1 Questions
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Question : 78
Total: 100
In the experiment of calibration of voltmeter, a standard cell of e.m.f. 1.1 volt is balanced against 440 cm of potential wire. The potential difference across the ends of resistance is found to balance against 220 cm of the wire. The corresponding reading of voltmeter is 0.5 volt. The error in the reading of voltmeter will be:
[Online April 12, 2014]
– 0. 15 volt
0.15 volt
0.5 volt
– 0.05 volt
Validate
Solution:
In a voltmeter
V
∝
l
V
=
k
l
Now, it is given
E
=
1.1
volt for
l
1
=
440
cm
and
V
=
0.5
volt for
l
2
=
220
cm
Let the error in reading of voltmeter be
Δ
V
then,
1.1
=
400
K
and
(
0.5
−
Δ
V
)
=
220
K
⇒
1.1
440
=
0.5
−
Δ
V
220
∴
Δ
V
=
−
0.05
volt
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