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JEE Main Physics Class 11 Physical world and Measurements Part 2 Questions
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© examsnet.com
Question : 97
Total: 100
If the length of the pendulum in pendulum clock increases by
0.1
%
, then the error in time per day is
[26 Aug 2021 Shift 2]
86.4
s
4.32
s
43.2
s
8.64
s
Validate
Solution:
Increase in length of pendulum is 0.1%.
i.e.
Δ
L
L
×
100
=
0.1
Time period of pendulum is given by
T
=
2
π
√
L
g
Here, 2 π and g are constant.
Δ
T
T
×
100
=
1
2
Δ
L
L
×
100
⇒
Δ
T
T
×
100
=
1
2
×
0.1
Δ
T
=
0.05
×
T
100
In one single day, the time in seconds is
T
=
24
×
60
×
60
=
86400
s
∴
Δ
T
=
0.05
×
86400
100
=
43.2
s
Thus, the error in time per day is 43.2 s.
© examsnet.com
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