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JEE Main Physics Class 11 Physical world and Measurements Part 3 Questions
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© examsnet.com
Question : 24
Total: 25
In a vernier calliper, when both jaws touch each other, zero of the vernier scale shifts towards left and its
4
th
division coincides exactly with a certain division on main scale. If 50 vernier scale divisions equal to 49 main scale divisions and zero error in the instrument is
0.04
mm
then how many main scale divisions are there in
1
cm
?
[6 Apr 2024 Shift 2]
40
5
20
10
Validate
Solution:
👈: Video Solution
4
th
division coincides with
3
rd
division then
0.004
cm
=
4
VSD
−
3
MSD
49
MSD
=
50
VSD
1
MSD
=
1
N
cm
0.004
=
4
{
49
50
MSD
}
−
3
MSD
0.004
=
(
196
50
−
3
)
(
1
N
)
N
=
46
50
×
1000
4
=
46
×
1000
200
=
230
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