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Test Index
JEE Main Physics Class 11 Properties of Solids and Liquids Questions Part 1 Questions
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© examsnet.com
Question : 2
Total: 100
Two tubes of radii
r
1
and
r
2
, and lengths
l
1
and
l
2
, respectively, are connected in series and a liquid flows through each of them in streamline conditions.
P
1
and
P
2
are pressure differences across the two tubes. If
P
2
is
4
P
1
and
l
2
is
l
1
4
, then the radius
r
2
will be equal to:
[Online April 9, 2017]
r
1
2
r
1
4
r
1
r
1
2
Validate
Solution:
The volume of liquid flowing through both the tubes i.e., rate of flow of liquid is same.
Therefore,
V
=
V
1
=
V
2
i.e.,
π
P
1
r
1
4
8
η
l
1
=
π
P
2
r
2
4
8
n
l
2
Or
P
1
r
1
4
l
1
=
P
2
r
2
4
l
2
∵
P
2
=
4
P
1
and
l
2
=
l
1
∕
4
P
1
r
1
4
l
1
=
4
P
1
r
2
4
l
1
∕
4
⇒
r
2
4
=
r
1
4
16
r
2
=
r
1
∕
2
© examsnet.com
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