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JEE Main Physics Class 11 Properties of Solids and Liquids Questions Part 1 Questions
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© examsnet.com
Question : 30
Total: 100
An air bubble of radius
0.1
c
m
is in a liquid having surface tension
0.06
N
∕
m
and density
10
3
k
g
∕
m
3
. The pressure inside the bubble is
1100
N
m
−
2
greater than the atmospheric pressure. At what depth is the bubble below the surface of the liquid?
(
g
=
9.8
m
s
−
2
)
[Online April 11, 2014]
0.1
m
0.15
m
0.20
m
0.25
m
Validate
Solution:
Given:
Radius of air bubble,
r
=
0.1
c
m
=
10
−
3
m
Surface tension of liquid,
S
=
0.06
N
∕
m
=
6
×
10
−
2
N
∕
m
Density of liquid,
ρ
=
10
3
k
g
∕
m
3
Excess pressure inside the bubble,
ρ
exe
=
1100
N
m
−
2
Depth of bubble below the liquid surface,
h
=
?
As we know,
ρ
Excess
=
h
ρ
g
+
2
s
r
⇒
1100
=
h
×
10
3
×
9.8
+
2
×
6
×
10
−
2
10
−
3
⇒
1100
=
9800
h
+
120
⇒
9800
h
=
1100
−
120
⇒
h
=
980
9800
=
0.1
m
© examsnet.com
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