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JEE Main Physics Class 11 Properties of Solids and Liquids Questions Part 1 Questions
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© examsnet.com
Question : 50
Total: 100
A mass of 50g of water in a closed vessel, with surroundings at a constant temperature takes 2 minutes to cool from 30°C to 25°C. A mass of 100g of another liquid in an identical vessel with identical surroundings takes the same time to cool from 30° C to 25° C. The specific heat of the liquid is :
(The water equivalent of the vessel is 30g.)
[Online April 25, 2013]
2.0 kcal/kg
7 kcal/kg
3 kcal/kg
0.5 kcal/kg
Validate
Solution:
As the surrounding is identical, vessel is identical time taken to cool both water and liquid (from 30°C to 25°C) is same 2 minutes, therefore
(
d
Q
d
t
)
water
=
(
d
Q
d
t
)
liquid
or,
(
m
W
C
W
+
W
)
Δ
T
t
=
(
m
L
C
L
+
W
)
Δ
T
t
(W = water equivalent of the vessel)
or
,
m
w
C
w
=
m
L
C
L
∴
Specific heat of liquid
,
C
L
=
m
W
C
W
m
L
=
50
×
1
100
=
0.5
k
c
a
l
∕
k
g
© examsnet.com
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