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Test Index
JEE Main Physics Class 11 Properties of Solids and Liquids Questions Part 1 Questions
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© examsnet.com
Question : 58
Total: 100
Water is flowing through a horizontal tube having crosssectional areas of its two ends being
A
and
A
′
such that the ratio
A
∕
A
′
is 5 . If the pressure difference of water between the two ends is
3
×
10
5
N
m
−
2
, the velocity of water with which it enters the tube will be (neglect gravity effects)
[Online May 12, 2012 ]
5
m
s
−
1
10
m
s
−
1
25
m
s
−
1
50
√
10
m
s
−
1
Validate
Solution:
According to Bernoulli’s theorem
P
1
+
1
2
ρ
v
1
2
=
P
2
+
1
2
ρ
v
2
2
.....(i)
From question,
P
1
−
P
2
=
3
×
10
5
,
A
1
A
2
=
5
According to equation of continuity
A
1
v
1
=
A
2
v
2
or,
A
1
A
2
=
v
2
v
1
=
5
⇒
v
2
=
5
v
1
From equation (i)
P
1
−
P
2
=
1
2
ρ
(
v
2
2
−
v
1
2
)
or
3
×
10
5
=
1
2
×
1000
(
5
v
1
2
−
v
1
2
)
⇒
600
=
6
v
1
×
4
v
1
⇒
v
1
2
=
25
∴
v
1
=
5
m
∕
s
© examsnet.com
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