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JEE Main Physics Class 11 Properties of Solids and Liquids Questions Part 1 Questions
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© examsnet.com
Question : 61
Total: 100
A large number of liquid drops each of radius
r
coalesce to from a single drop of radius
R
. The energy released in the process is converted into kinetic energy of the big drop so formed. The speed of the big drop is (given, surface tension of liquid
T
,
density
ρ
)
[Online April 19, 2014, 2012]
√
T
ρ
(
1
r
−
1
R
)
√
2
T
ρ
(
1
r
−
1
R
)
√
4
T
ρ
(
1
r
−
1
R
)
√
6
T
ρ
(
1
r
−
1
R
)
Validate
Solution:
When drops combine to form a single drop of radius
R
. Then energy released,
E
=
4
π
T
R
3
[
1
r
−
1
R
]
If this energy is converted into kinetic energy then
1
2
m
v
2
=
4
π
R
3
T
[
1
r
−
1
R
]
1
2
×
[
4
3
π
R
3
ρ
]
v
2
=
4
π
R
3
T
[
1
r
−
1
R
]
v
2
=
6
T
ρ
[
1
r
−
1
R
]
v
=
√
6
T
ρ
[
1
r
−
1
R
]
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