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Test Index
JEE Main Physics Class 11 Properties of Solids and Liquids Questions Part 1 Questions
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© examsnet.com
Question : 63
Total: 100
A wooden wheel of radius
R
is made of two semicircular part (see figure). The two parts are held together by a ring made of a metal strip of cross sectional area
S
and length L.
L
is slightly less than
2
π
R
. To fit the ring on the wheel, it is heated so that its temperature rises by
Δ
T
and it just steps over the wheel. As it cools down to surrounding temperature, it presses the semicircular parts together. If the coefficient of linear expansion of the metal is
α
,
and its Young's modulus is
Y
,
the force that one part of the wheel applies on the other part is:
[2012]
2
π
S
Y
α
Δ
T
S
Y
α
Δ
T
π
S
Y
α
Δ
T
2
S
Y
α
Δ
T
Validate
Solution:
The Young modulus is given as
Y
=
{stress
strain
=
F
∕
S
Δ
L
∕
L
Here
,
Δ
L
=
2
π
Δ
R
L
=
2
π
R
Y
=
F
S
2
π
Δ
R
×
2
π
R
⇒
Y
=
F
R
S
.
Δ
R
......(i)
The coefficient of linear expansion
α
=
Δ
R
R
Δ
T
⇒
Δ
R
R
=
α
.
Δ
T
⇒
R
Δ
R
=
1
α
Δ
T
.......(ii)
From equation (i) and (ii)
Y
=
F
S
.
α
Δ
T
⇒
F
=
Y
.
S
.
α
Δ
T
∴
The ring is pressing the wheel from both sides, Thus
F
net
=
2
F
=
2
Y
S
α
Δ
T
© examsnet.com
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