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JEE Main Physics Class 11 Properties of Solids and Liquids Questions Part 2 Questions
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© examsnet.com
Question : 26
Total: 100
A soap bubble of radius
3
cm
is formed inside the another soap bubble of radius
6
cm
. The radius of an equivalent soap bubble which has the same excess pressure as inside the smaller bubble with respect to the atmospheric pressure is .......... cm.
[26 Aug 2021 Shift 1]
Your Answer:
Validate
Solution:
The given situation is shown below
r
A
=
6
cm
r
B
=
3
cm
Excess pressure inside the soap bubble is given by
(
Δ
p
)
excess
=
4
S
r
A
+
4
S
r
B
According to the given question,
4
S
r
A
+
4
S
r
B
=
4
S
R
eq
⇒
1
r
A
+
1
r
B
=
1
R
eq
⇒
1
6
+
1
3
=
1
R
eq
⇒
1
+
2
6
=
1
R
eq
⇒
1
R
eq
=
1
2
⇒
R
eq
=
2
cm
© examsnet.com
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