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JEE Main Physics Class 11 Properties of Solids and Liquids Questions Part 2 Questions
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Question : 32
Total: 100
A hydraulic press can lift
100
k
g
when a mass 'm' is placed on the smaller piston. It can lift
k
g
when the diameter of the larger piston is increased by 4 times and that of the smaller piston is decreased by 4 times keeping the same mass 'm' on the smaller piston.
[24feb2021shift1]
Your Answer:
Validate
Solution:
$ \;{100 × g}/{A_{2}}=\;{m g}/{A_{1}}(A_{1}
Let
m
mass can lift
M
0
in second case then
M
0
g
16
A
2
=
m
g
A
1
16
(
∵
A
=
π
d
2
4
)
From equation (i) and (ii), we get
M
0
16
×
100
=
16
M
0
=
25600
k
g
© examsnet.com
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