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Test Index
JEE Main Physics Class 11 Properties of Solids and Liquids Questions Part 2 Questions
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© examsnet.com
Question : 45
Total: 100
Water flows in a horizontal tube (see figure). The pressure of water changes by
700
N
m
−
2
between
A
and
B
where the area of cross section are
40
c
m
2
and
20
c
m
2
, respectively. Find the rate of flow of water through the tube. (density of water
=
1000
k
g
m
−
3
)
[9 Jan. 2020 (I)]
3020
c
m
3
∕
s
2720
c
m
3
∕
s
2420
c
m
3
∕
s
1810
c
m
3
∕
s
Validate
Solution:
According to question, area of cross-section at
A
a
A
=
40
c
m
2
and at
B
,
a
B
=
20
c
m
2
Let velocity of liquid flow at
A
,
=
V
A
and at
B
,
=
V
B
Using equation of continuity
a
A
V
A
=
a
B
V
B
40
V
A
=
20
V
B
⇒
2
V
A
=
V
B
Now, using Bernoulli's equation
P
A
+
1
2
ρ
V
A
2
=
P
B
+
1
2
ρ
V
B
2
⇒
P
A
−
P
B
=
1
2
ρ
(
V
B
2
−
V
A
2
)
⇒
Δ
P
=
1
2
1000
(
V
B
2
−
V
B
2
4
)
⇒
Δ
P
=
500
×
3
V
B
2
4
⇒
V
B
=
√
(
Δ
P
)
×
4
1500
=
√
(
700
)
×
4
1500
m
∕
s
=
1.37
×
10
2
c
m
∕
s
Volume flow rate
Q
=
a
B
×
v
B
=
20
×
100
×
V
B
=
2732
c
m
3
∕
s
≈
2720
c
m
3
∕
s
© examsnet.com
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