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JEE Main Physics Class 11 Properties of Solids and Liquids Questions Part 2 Questions
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Question : 53
Total: 100
A bakelite beaker has volume capacity of
500
c
c
at
30
°
C
. When it is partially filled with
V
m
volume (at
30
°
C
)
of mercury, it is found that the unfilled volume of the beaker remains constant as temperature is varied. If
γ
(
beaker)
=
6
×
10
−
6
°
C
−
1
and
γ
(
mercury
)
=
1.5
×
10
−
4
°
C
−
1
,
where
gamma
is the coefficient of volume expansion, then
V
m
(in cc) is close to __________.
[NA Sep. 03,2020 (I)]
Your Answer:
Validate
Solution:
Volume capacity of beaker,
V
0
=
500
c
c
V
b
=
V
0
+
V
0
γ
beaker
Δ
T
When beaker is partially filled with
V
m
volume of mercury,
V
b
1
=
V
m
+
V
m
γ
m
Δ
T
Unfilled volume
(
V
0
−
V
m
)
=
(
V
b
−
V
m
1
)
⇒
V
0
γ
beaker
=
V
m
γ
M
∴
V
m
=
V
0
γ
beaker
γ
M
or,
V
m
=
500
×
6
×
10
−
6
1.5
×
10
−
4
=
20
c
c
.
© examsnet.com
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