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JEE Main Physics Class 11 Properties of Solids and Liquids Questions Part 2 Questions
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© examsnet.com
Question : 57
Total: 100
A bullet of mass 5 g, travelling with a speed of 210 m/s, strikes a fixed wooden target. One half of its kinetics energy is converted into heat in the bullet while the other half is converted into heat in the wood. The rise of temperature of the bullet if the specific heat of its material is 0.030 cal/(g – ºC) (1 cal =
4.2
×
10
7
ergs) close to :
[Sep. 05, 2020 (I)]
87.5ºC
83.3ºC
119.2ºC
38.4ºC
Validate
Solution:
According to question, one half of its kinetic energy is converted into heat in the wood.
1
2
m
v
2
×
1
2
=
m
s
Δ
T
⇒
Δ
T
=
v
2
4
×
s
=
210
×
210
4
×
4.2
×
0.3
×
1000
=
87.5
°
C
© examsnet.com
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