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JEE Main Physics Class 11 Properties of Solids and Liquids Questions Part 2 Questions
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© examsnet.com
Question : 6
Total: 100
Two wires of same length and radius are joined end to end and loaded. The Young's modulii of the materials of the two wires are
Y
1
and
Y
2
. The combination behaves as a single wire then its Young's modulus is :
[25 Jul 2021 Shift 1]
Y
=
2
Y
1
Y
2
3
(
Y
1
+
Y
2
)
Y
=
2
Y
1
Y
2
Y
1
+
Y
2
Y
=
Y
1
Y
2
2
(
Y
1
+
Y
2
)
Y
=
Y
1
Y
2
Y
1
+
Y
2
Validate
Solution:
In series combination
Δ
l
=
l
1
+
l
2
Y
=
F
∕
A
Δ
l
∕
l
⇒
Δ
l
=
F
l
A
Y
⇒
Δ
l
∝
l
Y
Equivalent length of rod after joing is
=
2
l
As, lengths are same and force is also same in series
Δ
l
=
Δ
l
1
+
Δ
l
2
l
c
q
Y
c
q
=
l
Y
1
+
l
Y
2
⇒
2
l
Y
=
l
Y
1
+
l
Y
2
∴
Y
=
2
Y
1
Y
2
Y
1
+
Y
2
© examsnet.com
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