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JEE Main Physics Class 11 System of Particles and Rotational Motion Part 1 Questions
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© examsnet.com
Question : 25
Total: 100
A circular disc
D
1
of mass
M
and radius
R
has two identical
discs
D
2
and
D
3
of the same mass
M
and radius
R
attached rigidly at its opposite ends (see figure). The moment of inertia of the system about the axis OO', passing through the centre of
D
1
,
as shown in the figure, will be :
[11 Jan. 2019 II]
M
R
2
3
M
R
2
4
5
M
R
2
2
3
M
R
2
Validate
Solution:
Moment of inertia of
disc
D
1
about
O
O
′
=
I
1
=
M
R
2
2
M.O.I of
D
2
about
O
O
′
=
I
2
=
1
2
(
M
R
2
2
)
+
M
R
2
=
M
R
2
4
+
M
R
2
M.O.I of
D
3
about
O
O
′
=
I
3
=
1
2
(
M
R
2
2
)
+
M
R
2
=
M
R
2
4
+
M
R
2
so, resultant M.O.I about
O
O
′
is
I
=
I
1
+
I
2
+
I
3
⇒
I
=
M
R
2
2
+
2
(
M
R
2
4
+
M
R
2
)
=
M
R
2
2
+
M
R
2
2
+
2
M
R
2
=
3
M
R
2
© examsnet.com
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