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JEE Main Physics Class 11 System of Particles and Rotational Motion Part 1 Questions
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© examsnet.com
Question : 42
Total: 100
A slender uniform rod of mass
M
and length
ell
is pivoted at one end so that it can rotate in a vertical plane (see figure). There is negligible friction at the pivot. The free end is held vertically above the pivot and then released. The angular acceleration of the rod when it makes an angle
θ
with the vertical is
[2017]
3
g
2
l
cos
θ
2
g
3
l
cos
θ
3
g
2
l
sin
θ
2
g
2
l
sin
θ
Validate
Solution:
Torque at angle
θ
τ
=
M
g
sin
θ
.
l
2
Also
τ
=
l
α
∴
l
α
=
M
g
sin
θ
l
2
M
l
2
3
.
α
=
M
g
sin
θ
l
2
[
∵
I
r
o
d
=
M
l
2
3
]
⇒
l
α
3
=
g
sin
θ
2
∴
α
=
3
g
sin
θ
2
l
© examsnet.com
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