JEE Main Physics Class 11 System of Particles and Rotational Motion Part 1 Questions

By the theorem of perpendicular axes,
I=IEF+IGH
Here, I is the moment of inertia of square lamina about an axis through O and perpendicular to its plane.
∴IEF=IGH( By Symmetry of Figure ) ∴IEF=

I

2

......(i)
Again, by the same theorem I=IAC+IBD=2IAC
(∴IAC=IBD by symmetry of the figure)
∴IAC=

I

2

.......(ii)
From (i) and (ii), we get, IEF=IAC