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Test Index
JEE Main Physics Class 11 System of Particles and Rotational Motion Part 1 Questions
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© examsnet.com
Question : 96
Total: 100
A circular disc
X
of radius
R
is made from an iron plate of thickness
t
,
and another disc
Y
of radius
4
R
is made from an iron plate of thickness
t
4
.
Then the relation between the moment of inertia
I
X
and
I
I
is
[2003]
I
Y
=
32
I
X
I
Y
=
16
I
X
I
Y
=
I
X
I
Y
=
64
I
X
Validate
Solution:
We know that density
(
d
)
=
mass
(
M
)
volume
(
V
)
∴
M
=
d
×
V
=
d
×
(
π
R
2
×
t
)
The moment of inertia of a disc is given by
I
=
1
2
M
R
2
∴
I
x
=
1
2
M
x
R
x
2
=
1
2
(
d
×
π
R
2
×
t
)
R
2
=
π
d
2
t
×
R
4
I
y
=
1
2
M
y
R
y
2
=
1
2
[
π
(
4
R
2
)
(
1
4
)
d
]
×
(
4
R
)
2
∴
I
X
I
Y
=
t
X
R
X
4
t
Y
R
Y
4
=
t
×
R
4
t
4
×
(
4
R
)
4
=
1
64
© examsnet.com
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