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JEE Main Physics Class 11 System of Particles and Rotational Motion Part 2 Questions
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© examsnet.com
Question : 14
Total: 100
Choose the correct answer from the options given below :
List-I
List-II
(A)
Moment of inertia of solid sphere of radius R about any tangent.
(I)
5
3
M
R
2
(B)
Moment of inertia of hollow sphere of radius (R) about any tangent.
(II)
7
5
M
R
2
(C)
Moment of inertia of circular ring of radius (R) about its diameter.
(III)
1
4
M
R
2
(D)
Moment of inertia of circular disc of radius (R) about any diameter.
(IV)
1
2
M
R
2
[28-Jun-2022-Shift-1]
A - II, B - I, C - IV, D - III
A - I, B - II, C - IV, D - III
A - II, B - I, C - III, D - IV
A - I, B - II, C - III, D - IV
Validate
Solution:
(A) Moment of inertia of solid sphere of radius
R
about a tangent
=
2
5
M
R
2
+
M
R
2
=
7
5
M
R
2
⇒
A
−
(
I
I
)
(B) Moment of inertia of hollow sphere of radius
R
about a tangent
=
2
3
M
R
2
+
M
R
2
=
5
3
M
R
2
⇒
B
−
(
I
)
(C) Moment of inertia of circular ring of radius
(
R
)
about its diameter
=
(
M
R
2
)
2
⇒
C
−
(
IV
)
(D) Moment of inertia of circular disc of radius (
R
) about any diameter
=
M
R
2
∕
2
2
=
M
R
2
4
⇒
D
−
(
III
)
© examsnet.com
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