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JEE Main Physics Class 11 System of Particles and Rotational Motion Part 2 Questions
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Question : 51
Total: 100
A body rotating with an angular speed of 600 rpm is uniformly accelerated to 1800 rpm in 10 sec. The number of rotations made in the process is___.
[20 Jul 2021 Shift 2]
Your Answer:
Validate
Solution:
Given, initial angular speed,
ω
0
=
600
r
p
m
=
10
r
p
s
Final angular speed,
ω
F
=
1800
r
p
m
=
30
r
p
s
Time,
t
=
10
s
∵
We know that
ω
F
=
ω
0
+
α
t
⇒
30
=
10
+
α
×
10
⇒
30
−
10
10
=
α
⇒
α
=
20
10
=
2
r
p
s
2
Angular displacement is calculated by the rotational equation of motion as
θ
=
ω
0
t
+
1
2
α
t
2
where,
θ
is the angular displacement.
⇒
θ
=
10
×
10
+
1
2
×
2
×
(
10
)
2
⇒
θ
=
100
+
100
⇒
θ
=
200
r
a
d
Number of rotations
=
θ
2
π
=
200
2
π
=
31.8
≈
32
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