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JEE Main Physics Class 11 System of Particles and Rotational Motion Part 2 Questions

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Question : 59

Total: 100

Moment of inertia (M.I.) of four bodies, having same mass and radius, are reported as;
I1= M.I. of thin circular ring about its diameter,
I2= M.I. of circular disc about an axis perpendicular to the disc and going through the centre,
I3= M.I. of solid cylinder about its axis and I4= M.I. of solid sphere about its diameter. Then :

[24feb2021shift1]

I1+I3<I2+I4
I1+I2=I3+‌
5
2
I4
I1=I2=I3>I4
I1=I2=I3<I4

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