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JEE Main Physics Class 11 System of Particles and Rotational Motion Part 2 Questions

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Question : 64

Total: 100

As shown in fig. when a spherical cavity (centred at O ) of radius 1 is cut out of a uniform sphere of radius R (centred at C ), the centre of mass of remaining (shaded) part of sphere is at G, i.e on the surface of the cavity. R can be determined by the equation:

[8 Jan. 2020 II]

(R2+R+1)(2−R)=1
(R2−R−1)(2−R)=1
(R2−R+1)(2−R)=1
(R2+R−1)(2−R)=1

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