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JEE Main Physics Class 11 System of Particles and Rotational Motion Part 2 Questions
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© examsnet.com
Question : 95
Total: 100
Consider a uniform cubical box of side a on a rough floor that is to be moved by applying minimum possible force
F
at
a
point
b
above its centre of mass (see figure). If the coefficient of friction is
µ
=
0.4
,
the maximum possible value of
100
×
b
a
for box not to topple before moving is ______.
[NA 7 Jan. 2020 II]
Your Answer:
Validate
Solution:
For the box to be slide
F
=
µ
m
g
=
0.4
m
g
For no toppling
F
(
a
2
+
b
)
≤
m
g
a
2
⇒
&
0.4
m
g
(
a
2
+
b
)
≤
m
g
a
2
⇒
0.2
a
+
0.4
b
≤
0.5
a
⇒
b
a
≤
3
4
i.e.
b
≤
0.75
a
but this is not possible.
As the maximum value of
b
can be equal to
0.5
a
.
⇒
100
b
a
=
50
© examsnet.com
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