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JEE Main Physics Class 11 Thermodynamics Part 2 Questions
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Question : 22
Total: 82
The Thermodynamic process, in which internal energy of the system remains constant is
[11-Apr-2023 shift 2]
Isobaric
Isochoric
Adiabatic
Isothermal
Validate
Solution:
∆
U
=
nC
V
∆
T
, for all process
For isothermal process,
∆
T
=
0
So,
∆
U
=
0
That means internal energy of system remains constant.
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