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JEE Main Physics Class 11 Thermodynamics Part 2 Questions
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© examsnet.com
Question : 44
Total: 82
A sample of gas at temperature
T
is adiabatically expanded to double its volume. The work done by the gas in the process is
(
.
given,
γ
=
3
2
)
:
[1-Feb-2023 Shift 1]
W
=
T
R
[
√
2
−
2
]
W
=
T
R
[
√
2
−
2
]
W
=
R
T
[
2
−
√
2
]
W
=
R
T
[
2
−
√
2
]
Validate
Solution:
T
1
V
1
γ
−
1
=
T
2
V
2
γ
−
1
T
V
1
∕
2
=
T
2
(
2
V
)
1
∕
2
T
2
=
T
√
2
W
=
R
(
T
1
−
T
2
)
γ
−
1
=
R
(
T
−
T
√
2
)
1
2
=
R
T
(
2
−
√
2
)
© examsnet.com
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