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JEE Main Physics Class 11 Thermodynamics Part 2 Questions
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© examsnet.com
Question : 60
Total: 82
In a carnot engine, the temperature of reservoir is
527
∘
C
and that of sink is
200
K
. If the work done by the engine when it transfers heat from reservoir to sink is
12000
kJ
, the quantity of heat absorbed by the engine from reservoir is ____
×
10
6
J
.
[27-Jun-2022-Shift-1]
Your Answer:
Validate
Solution:
η
=
1
−
T
2
T
1
=
1
−
200
800
=
3
4
∴
η
=
W
Q
1
⇒
3
4
=
12000
×
10
3
Q
1
⇒
Q
1
=
16
×
10
6
J
© examsnet.com
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