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JEE Main Physics Class 11 Waves Part 1 Questions
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Question : 14
Total: 100
In a resonance tube experiment when the tube is filled with water up to a height of 17.0 cm from bottom, it resonates with a given tuning fork. When the water level is raised the next resonance with the same tuning fork occurs at a height of 24.5 cm. If the velocity of sound in air is 330 m/s, the tuning fork frequency is :
[Sep. 05, 2020 (I)]
2200 Hz
550 Hz
1100 Hz
3300 Hz
Validate
Solution:
Here,
l
1
=
17
c
m
and
l
2
=
24.5
c
m
,
V
=
330
m
∕
s
f
=
?
λ
=
2
(
l
2
−
l
1
)
=
2
×
(
24.5
−
17
)
=
15
c
m
Now, from
v
=
f
λ
⇒
330
=
λ
×
15
×
10
−
2
∴
λ
=
330
15
×
100
=
1100
×
100
5
=
2200
H
z
© examsnet.com
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