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JEE Main Physics Class 11 Waves Part 1 Questions
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© examsnet.com
Question : 53
Total: 100
Two sitar strings, A and B, playing the note 'Dha' are slightly out of tune and produce beats and frequency 5 Hz. The tension of the string B is slightly increased and the beat frequency is found to decrease by 3 Hz . If the frequency of A is 425 Hz, the original frequency of B is
[Online April 16, 2018]
430 Hz
428 Hz
422 Hz
420 Hz
Validate
Solution:
n
A
=
425
H
z
,
n
B
=
?
Beat frequency x = 5 Hz which is decreasing (5 → 3) after increasing the tension of the string B.
Also tension of string B increasing so
n
B
↑
(
∵
n
∝
√
T
)
Hence
n
B
↑
−
n
A
=
x
↓
→
correct
n
B
↑
−
n
A
=
x
↓
→
incorrect
∴
n
B
=
n
A
−
x
=
425
−
5
=
420
H
z
© examsnet.com
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