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JEE Main Physics Class 11 Waves Part 1 Questions
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© examsnet.com
Question : 59
Total: 100
Two engines pass each other moving in opposite directions with uniform speed of 30 m/s. One of them is blowing a whistle of frequency 540 Hz. Calculate the frequency heard by driver of second engine before they pass each other. Speed of sound is 330 m/sec:
[Online April 9, 2016]
450 Hz
540 Hz
270 Hz
648 Hz
Validate
Solution:
We know that the apperent frequency
f
′
=
(
v
−
v
0
v
−
v
s
)
f
from Doppler's effect
where
v
0
=
v
s
=
30
m
∕
s
,
velocity of observer and source
Speed of sound
v
=
330
m
∕
s
∴
f
′
=
330
+
30
330
−
30
×
540
=
648
H
z
∵
Frequency of whistle
(
f
)
=
540
H
z
© examsnet.com
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