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JEE Main Physics Class 11 Waves Part 1 Questions
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© examsnet.com
Question : 88
Total: 100
While measuring the speed of sound by performing a resonance column experiment, a student gets the first resonance condition at a column length of 18 cm during winter. Repeating the same experiment during summer, she measures the column length to be x cm for the second resonance. Then
[2008]
18 > x
x > 54
54 > x > 36
36 > x > 18
Validate
Solution:
Fundamental frequency for first resonant length
v
=
v
4
l
1
=
v
4
×
18
(in winter)
Fundamental frequency for second resonant length
v
′
=
3
v
′
4
l
2
=
3
v
′
4
x
(in summer)
According to questions,
∴
v
4
×
18
=
3
v
′
4
×
x
∴
x
=
3
×
18
×
v
′
v
∴
x
=
54
×
v
′
v
c
m
v
′
>
v
because velocity of light is greater in summer as compared to winter
(
v
∝
√
T
)
∴
x
>
54
c
m
© examsnet.com
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