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JEE Main Physics Class 11 Waves Part 2 Questions
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© examsnet.com
Question : 42
Total: 48
The equations of two waves are given by:
y
1
=
5
sin
2
π
(
x
−
v
t
)
cm
y
2
=
3
sin
2
π
(
x
−
v
t
+
1.5
)
cm
These waves are simultaneously passing through a string. The amplitude of the resulting wave is:
[24-Jun-2022-Shift-1]
2
cm
4
cm
5.8
cm
8
cm
Validate
Solution:
y
1
=
5
sin
(
2
π
x
−
2
π
v
t
)
y
2
=
3
sin
(
2
π
x
−
2
π
v
t
+
3
π
)
⇒
Phase difference
=
3
π
⇒
A
n
e
t
=
√
A
1
2
+
A
2
2
+
2
A
1
A
2
cos
(
3
π
)
⇒
A
n
e
t
=
2
cm
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