Total force required to lift maximum load capacity against frictional force = 400 N Ftotal=Mg+ friction =2000×10+4000 =20,000+4000=24000N Using power, P=F×v 60×746=24000×v ⇒v=1.86m∕s≈1.9m∕s Hence speed of the elevator at full load is close to 1.9ms−1