From momentum conservation in perpendicular direction of initial motion. mu1sinθ1=10mv1sinθ2 ...(i) It is given that energy of m reduced by half. If u1 be velocity of m after collision, then (
1
2
mu2)
1
2
=
1
2
mu12 ⇒u1=
u
√2
If v1 be the velocity of mass 10m after collision, then