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JEE Main Physics Class 11 Work, Energy and Power Part 2 Questions
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© examsnet.com
Question : 2
Total: 100
A force
→
F
=
(
2
+
3
x
)
^
i
acts on a particle in the
x
direction where
F
is in newton and
x
is in meter. The work done by this force during a displacement from
x
=
0
to
x
=
4
m
, is ________
mJ.
[11-Apr-2023 shift 1]
Your Answer:
Validate
Solution:
→
F
=
(
2
+
3
x
)
i
w
=
4
∫
0
F
⋅
dx
=
4
∫
0
(
2
+
3
x
)
⋅
dx
w
=
(
2
x
+
3
x
2
2
)
4
=
(
8
+
24
)
w
=
32
J
© examsnet.com
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