Given,
The mass of the first ball,
m1=10kg The mass of the second ball,
m2=20kg The initial velocity of the first ball,
u1=10√3m/s The initial velocity of the second ball,
u2=0m/s The final velocity of the first ball,
v1=0m/s The final velocity of the first piece of the second ball,
v2=10m/s Let's consider the final velocity of the second piece of the second ball
=v2 As shown in the figure,
The net external force on the system is to be zero. Hence, we can use the law of conservation of linear momentum in both directions.
lnx-direction the linear momentum conserved,
In
x-direction the linear momentum conserved,
m1U1x+m2U2x=m1v1x+m2v2x+m3V3x
⇒10(10√3)+0=10(0)+0+10v3cos30∘
⇒v3=20m/s Hence, the velocity of the ball moving at
30∘ with respect to the
X-axis is
20m/s.
So, the value of
x to the nearest integer is 20 .