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JEE Main Physics Class 11 Work, Energy and Power Part 3 Questions
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© examsnet.com
Question : 2
Total: 37
A body of
m
kg
slides from rest along the curve of vertical circle from point
A
to
B
in friction less path. The velocity of the body at
B
is :
(given,
R
=
14
m
,
g
=
10
m
∕
s
2
and
√
2
=
1.4
)
[4 Apr 2024 Shift 2]
19.8
m
∕
s
21.9
m
∕
s
16.7
m
∕
s
10.6
m
∕
s
Validate
Solution:
👈: Video Solution
Apply W.E.T. from A to B
⇒
W
mg
=
K
B
−
K
A
⇒
mg
×
(
R
√
2
+
R
)
=
1
2
m
v
B
2
−
0
{
v
A
=
0
rest
}
⇒
mgR
(
√
2
+
1
)
√
2
=
1
2
m
v
B
2
⇒
√
gR
2
(
√
2
+
1
)
√
2
=
v
B
⇒
√
10
×
14
×
2
(
2.4
)
1.4
=
v
B
⇒
21.9
=
v
B
Hence option (2) is correct
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