Given, number of mole, n=1 Heat supplied =Q Work done =Q∕5 By using first law of thermodynamics, ∆Q‌‌=∆U+∆W Q‌‌=∆U+Q∕5 ∆U‌‌=4Q∕5=nCv∆T. . . (i) where, CV is heat coefficient at constant volume and ∆T is change in temperature. Degree of freedom of diatomic gas, f=5 ∴‌‌Q=‌