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JEE Main Physics Class 12 Alternating Currents Part 2 Questions
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© examsnet.com
Question : 4
Total: 75
An ac source is connected in given series LCR circuit. The rms potential difference across the capacitor of
20
µ
F
is ______
V
.
[5 Apr 2024 Shift 1]
Your Answer:
Validate
Solution:
👈: Video Solution
X
L
=
ω
L
=
100
×
1
=
100
Ω
X
C
=
1
ω
C
=
1
100
×
20
×
10
−
6
=
500
Ω
Z
=
√
(
X
L
−
X
C
)
2
+
R
2
√
(
100
−
500
)
2
+
300
2
Z
=
500
Ω
i
rms
=
V
rms
Z
=
50
500
=
0.1
A
rms voltage across capacitor
V
rms
=
X
C
i
rms
=
500
×
0.1
=
50
V
© examsnet.com
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