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JEE Main Physics Class 12 Alternating Currents Part 2 Questions
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© examsnet.com
Question : 59
Total: 75
A circuit element
X
when connected to an a.c. supply of peak voltage
100
V
gives a peak current of
5
A
which is in phase with the voltage. A second element
Y
when connected to the same a.c. supply also gives the same value of peak current which lags behind the voltage by
π
2
. If
X
and
Y
are connected in series to the same supply, what will be the rms value of the current in ampere?
[29-Jul-2022-Shift-2]
10
√
2
5
√
2
5
√
2
5
2
Validate
Solution:
Element
X
should be resistive with,
R
=
100
5
=
20
Ω
Element
Y
should be inductive with,
X
L
=
100
5
=
20
Ω
When
X
and
Y
are connector in series,
Z
=
√
20
2
+
20
2
=
20
√
2
Ω
I
=
100
Z
=
100
20
√
2
=
5
√
2
i
rms
=
1
√
2
I
=
5
2
© examsnet.com
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